iT邦幫忙

第 12 屆 iThome 鐵人賽

DAY 27
0
Software Development

刷刷題 or Alan Becker's game 製作 is a question 系列 第 27

(Medium) 29. Divide Two Integers #水

  • 分享至 

  • xImage
  •  

Given two integers dividend and divisor, divide two integers without using multiplication, division, and mod operator.

Return the quotient after dividing dividend by divisor.

The integer division should truncate toward zero, which means losing its fractional part. For example, truncate(8.345) = 8 and truncate(-2.7335) = -2.

Note:

Assume we are dealing with an environment that could only store integers within the 32-bit signed integer range: [−2^31, 2^31 − 1]. For this problem, assume that your function returns 231 − 1 when the division result overflows.

Example 1:

Input: dividend = 10, divisor = 3
Output: 3
Explanation: 10/3 = truncate(3.33333..) = 3.

Example 2:

Input: dividend = 7, divisor = -3
Output: -2
Explanation: 7/-3 = truncate(-2.33333..) = -2.

Example 3:

Input: dividend = 0, divisor = 1
Output: 0
Example 4:

Input: dividend = 1, divisor = 1
Output: 1

Constraints:

-2^31 <= dividend, divisor <= 2^31 - 1
divisor != 0


Solution:
被除數 / 除數 = 商數
return 商數 <-- 取整數即可
如果 商數大於 2^32 -1 則回傳 2^32 -1

Code:

class Solution:
    def divide(self, dividend: int, divisor: int) -> int:
        quotient = dividend / divisor
        print(int(quotient))
        if int(quotient) > (pow(2,31)-1):
            return pow(2,31)-1
        return int(quotient)

Result:
https://ithelp.ithome.com.tw/upload/images/20201012/201115161aMDNXINHH.jpg


上一篇
(Easy) 28. Implement strStr()
下一篇
(Hard) 30. Substring with Concatenation of All Words
系列文
刷刷題 or Alan Becker's game 製作 is a question 30
圖片
  直播研討會
圖片
{{ item.channelVendor }} {{ item.webinarstarted }} |
{{ formatDate(item.duration) }}
直播中

尚未有邦友留言

立即登入留言